# extract

**URL:** https://community.mp3tag.de/t/extract/3889
**Category:** Support
**Created:** [October 12, 2006, 4:20pm UTC](https://community.mp3tag.de/t/extract/3889 "2006-10-12T16:20:25Z")
**Posts on this page:** 3
**Page:** 1

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### Author: ![mauriello](https://community.mp3tag.de/letter_avatar_proxy/v4/letter/m/278dde/32.png) [@mauriello](https://community.mp3tag.de/u/mauriello)
#### Post date: [October 12, 2006, 4:20pm UTC](https://community.mp3tag.de/t/extract/3889/1 "2006-10-12T16:20:25Z")

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I have field "song" ex number 021005. First two number are the year of production. how to exctract this two numbers and add 20 for to get in "year" field 2002?  
Sorry my bad english  
mauro

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### Author: ![Sebastian\_Mares](https://community.mp3tag.de/user_avatar/community.mp3tag.de/sebastian_mares/32/9285_2.png) [@Sebastian\_Mares](https://community.mp3tag.de/u/Sebastian_Mares)
#### Post date: [October 12, 2006, 4:33pm UTC](https://community.mp3tag.de/t/extract/3889/2 "2006-10-12T16:33:12Z")

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Action #1:  
_Action type:_ **Format value**  
_Field:_ **YEAR**  
_Formatstring:_ **20$mid(%song%,1,2)**

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### Author: ![system](https://community.mp3tag.de/uploads/default/original/2X/c/ce7035d426cb755a7916793326d23b465222a407.png) [@system](https://community.mp3tag.de/u/system)
#### Post date: [February 9, 2026, 12:19pm UTC](https://community.mp3tag.de/t/extract/3889/3 "2026-02-09T12:19:55Z")

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