# How to replace part of a string with a value from another tag?
**URL:** https://community.mp3tag.de/t/how-to-replace-part-of-a-string-with-a-value-from-another-tag/64833
**Category:** Support
**Created:** [May 27, 2024, 4:15pm UTC](https://community.mp3tag.de/t/how-to-replace-part-of-a-string-with-a-value-from-another-tag/64833 "2024-05-27T16:15:09Z")
**Posts on this page:** 4
**Page:** 1
### Author:  [@whoit](https://community.mp3tag.de/u/whoit)
#### Post date: [May 27, 2024, 4:15pm UTC](https://community.mp3tag.de/t/how-to-replace-part-of-a-string-with-a-value-from-another-tag/64833/1 "2024-05-27T16:15:09Z")
I'd like to replace part of a string (first 4 chars) from RELEASETIME with the full value of YEAR
For example:
ReleaseTime: 2007-08-27T22:00:00Z
Year: 2024
Result: 2024-08-27T22:00:00Z
I've tried creating a "Replace with regular expression" where:
field: RELEASETIME
reg ex: `^.{0,4}`
but there I can't see a way to use the value from field YEAR as a replacement.
---
### Author:  [@LyricsLover](https://community.mp3tag.de/u/LyricsLover)
#### Post date: [May 27, 2024, 4:21pm UTC](https://community.mp3tag.de/t/how-to-replace-part-of-a-string-with-a-value-from-another-tag/64833/2 "2024-05-27T16:21:29Z")
You could try
Convert Tag -\> Tag
Field:
`RELEASETIME`
Format string:
`$regexp(%RELEASETIME%,\d{4},%YEAR%)`
This would replace the first 4 digits in RELEASETIME with the content of YEAR.
---
### Author:  [@whoit](https://community.mp3tag.de/u/whoit)
#### Post date: [May 27, 2024, 5:06pm UTC](https://community.mp3tag.de/t/how-to-replace-part-of-a-string-with-a-value-from-another-tag/64833/3 "2024-05-27T17:06:45Z")
Works perfectly - thanks!
---
### Author:  [@system](https://community.mp3tag.de/u/system)
#### Post date: [June 26, 2024, 5:07pm UTC](https://community.mp3tag.de/t/how-to-replace-part-of-a-string-with-a-value-from-another-tag/64833/4 "2024-06-26T17:07:19Z")
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