# Year in new v3.32
**URL:** https://community.mp3tag.de/t/year-in-new-v3-32/70182
**Category:** Support
**Created:** [November 17, 2025, 4:38pm UTC](https://community.mp3tag.de/t/year-in-new-v3-32/70182 "2025-11-17T16:38:50Z")
**Posts on this page:** 4
**Page:** 1
### Author:  [@MrMix](https://community.mp3tag.de/u/MrMix)
#### Post date: [November 17, 2025, 4:38pm UTC](https://community.mp3tag.de/t/year-in-new-v3-32/70182/1 "2025-11-17T16:38:50Z")
Hello,
I believe something has changed from the previous v3.31f.
Despite the year format in musicbrainz (yyyy-mm or yyyy-mm-dd) I could see in column year just the year (yyyy) in v3.31f
Now in v3.32 I see in column year exactly the date imported from musicbrainz.
I did not changed the setting. Value `$meta_sep(year,\\)` - Field %year%
How can I just save the year like in the v3.31f ?
Thank you fro the help
MM
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### Author:  [@ohrenkino](https://community.mp3tag.de/u/ohrenkino)
#### Post date: [November 17, 2025, 4:43pm UTC](https://community.mp3tag.de/t/year-in-new-v3-32/70182/2 "2025-11-17T16:43:13Z")
Try an action of the type "Format value" or Convert\>Tag-Tag for YEAR
Format string: $num(%year%,1)
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### Author:  [@MrMix](https://community.mp3tag.de/u/MrMix)
#### Post date: [November 19, 2025, 5:08pm UTC](https://community.mp3tag.de/t/year-in-new-v3-32/70182/3 "2025-11-19T17:08:09Z")
Thank you.
I solved with Format value “Year“: $left(%year%,4)
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### Author:  [@system](https://community.mp3tag.de/u/system)
#### Post date: [December 19, 2025, 5:08pm UTC](https://community.mp3tag.de/t/year-in-new-v3-32/70182/4 "2025-12-19T17:08:11Z")
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