say i have a lot of folders in the uniform format of %artist% - yyyy-mm-dd - venue, city, state i.e Led Zeppelin - 1973-12-01 - Madison Square Garden, New York, NY with files named 01. %title%.flac 02. %title%.flac 03. %title%.flac 04. %title%.flac 05. %title%.flac 06. %title%.flac 07. %t…

actual final script for file renaming $regexp(%_directory%,(.*) - (\d+)_(\d+)_(\d+) (.*),$1 - 20$4-$2-$3 $5) note that the 2 and 3 are switched from your originally suggested expression, to yield YYYY-MM-DD

[image] jerryfreak: for some reason the post is getting autoformatted See here for some hints on how to post strings as they are: [image] Hints for asking Support Requests Support If you need support using Mp3tag, you can help the community members that …

To get the first part extracted, you could try: $regexp('Led Zeppelin - 1973-12-01 - Madison Square Garden, New York, NY',^(.).*? (.).*? - \d\d(\d\d)-(\d\d)-(\d\d) - .*,$1$2_$3$4$5) which lead to: "LZ_731201"

but im not trying to do a single folder im trying to parse from folders in same format, like Led Zeppelin - 1973-12-01 - Madison Square Garden, New York, NY Led Zeppelin - 1973-12-04 - Knickerbocker Arena, Albany, NY Led Zeppelin - 1973-12-07 - Spectrum, Philadelphia, PA Led Zeppelin - 1973-12-0…

To get just the date, try $regexp('Led Zeppelin - 1973-12-01 - Madison Square Garden, New York, NY',^.*? - \d\d(\d\d)-(\d\d)-(\d\d) - .*,$1$2$3) To get just the date, try $regexp('Led Zeppelin - 1973-12-01 - Madison Square Garden, New York, NY',^.*? - \d\d(\d\d)-(\d\d)-(\d\d) - .*,$1$2$3) [im…

i dont need to generate the initials, can type them in myself as i will run the script forhundreds of folders for one artist at a time. ideally i want it to ignore everything in the folder name and just parse the date if its easier i could bulk edit the folder names and take the artist out and add …

Have tried my suggestion [image] ohrenkino: To get just the date, try $regexp('Led Zeppelin - 1973-12-01 - Madison Square Garden, New York, NY',^.*? - \d\d(\d\d)-(\d\d)-(\d\d) - .*,$1$2$3) Instead of the real string, insert %_directory%: $regexp(%_directory%,^.*? - \d\d(\d\d)-(\d\d)-(\d\d)…

in which converter do i enter the above expression? nothing works when i put it in 'tag>filename' or 'filename>filename' (the latter of which requires two fields)

[image] jerryfreak: nothing works when i put it in 'tag filename' or ' Could you post a screendump - as that would be the right place.

i fixed your syntax from 'driectory' to 'directory' and its now parsing the folder name within tag>filename converter, normally i would use tag>filename converter and enter lz731201d%discnumber%_$num(%track%,2)_$replace(%title%, ,_) replacing lz731201 with $regexp(%_directory%,^.*? - \d\d(\d\d)-…

Parsing a portion of current folder name to rename files

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ohrenkino April 27, 2023, 9:19am 2

See here for some hints on how to post strings as they are: