Problem with $regexp and brackets

Support
1

I know this has been brought up before, but wondering if there is a fix. I have the following expression, which should replace all open brackets with nothing:

$regexp(%album%,[,)

As I understand, because "[" is a reserved character, it has to be surrounded in single quotes to parse correctly, which gives me this:

$regexp(%album%,'[',)

I also tried both of these.

$regexp(%album%,[[],)
$regexp(%album%,['['],)

None of these work. It seems that regardless of how I go about it, a "[" will always register as a special character within a regex, and there is no valid way to denote the character itself. Though I have a workaround for my specific case, it seems strange that there is no way to do this. Does anyone have any clues here?

2

It actually has to be the backslash to escape special characters:
\[

3

$regexp(%artist%,\'[',)
or without regex:
$replace(%artist%,'[',)

4

Ah, I was close! Much appreciated!