Remove parenthesis and its content from the Artist field

[tdog]

I need a regular expression that will convert the artist field from
Artist (some text) to Artist. I had this expression but lost it and can't find anymore.
Please help.

[LyricsLover]

Please use the search function in this forum. There are many existing solutions already.
(You can try to replace "parenthesis" with the search term "brackets".)

Or show us what you have tried so far and what is not working for you with real content in your ARTIST field.

BTW:
What do you want to do with ARTIST names starting with brackets and with or without spaces like

(ghost)
(hed) p.e.
(iam)warface

or
in(COMPLETE)in

[anon32189785]

@tdog

Artist (some text)

I'm not sure whether I understand your example? Here is my example:

Artista (some text 1)
Artiste (some text 2)
Artisti (some text 3)
Artisto (some text 4)
Artistu (some text 5)

find: (^.*?) (.*) // depending on your actual field this might need adjustment
replace: \1 // I use "Sublime Text" for my RegEx, other editors might use "$1"

Regexper

Regexper

[LyricsLover]

@anon32189785

(^.*?) (.*)

This would not work for ARTIST names with more then one word like in
Another Artist (with text to remove)

The preview shows that this would result in:
Another
and not the expected
Another Artist

[anon32189785]

@LyricsLover, thanks for the actual Mp3tag dialog with the necessary syntax. And of course you are right, but as I said above:

" -> find: (^.*?) (.*) // depending on your actual field this might need adjustment"

Here is the adjustment with an adjusted example:

Art ist a (some text 1)
Art ist e (some text 2)
Art ist i (some text 3)
Art ist o (some text 4)
Art ist u (some text 5)

adjusted find (and same replace):
Here is the adjustment with an adjusted example:

Art ist a (some text 1)
Art ist e (some text 2)
Art ist i (some text 3)
Art ist o (some text 4)
Art ist u (some text 5)

adjusted find (and same replace):

find: (^.*?)( \().*

visualized RegEx from:
Regexper*

[LyricsLover]

The first search result for "remove content in brackets" already shows:

Remove Parentesis & Square Brackets Content

You could try an action of the type "Replace with Regular Expression" Search string: \s*\(.* Replace with: (leave empty) Works for text where the round brackets are the first brackets, just like your example

Adjusted for Convert Tag -> Tag instead of an Action it would be
$regexp(%ARTIST%,'\s*\(.*',)
for the most easy variants of
Another Artist (with text to remove)

As long as the OP does not provide the actual real content of the ARTIST fields, we can only guess what would match it. The same applies to some of the more advanced examples mentioned above.

[tdog]

@LyricsLover

$regexp(%ARTIST%,'\s*(.*',)

Thanks.
$regexp(%ARTIST%,'\s*\(.*',) is what I was looking for. For some reason could not easily locate it in the forum.